Question
If 0.4x + 0.6y = 26 and x - y = 10, find x.
Solution
ATQ, 0.4x + 0.6y = 26 Multiply by 10: 4x + 6y = 260 ...(1) x - y = 10 => x = y + 10 ...(2) Put (2) into (1): 4(y+10) + 6y = 260 4y + 40 + 6y = 260 10y = 220 y = 22 x = y + 10 = 22 + 10 = 32
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