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    Question

    For given pair of equations, how many solutions are

    possible? 5x тИТ 2y = 12 and 10x тИТ 4y = 24
    B 1 Correct Answer Incorrect Answer
    C infinite Correct Answer Incorrect Answer
    D None of these Correct Answer Incorrect Answer

    Solution

    For a pair of linear equations a1x + b1y + c1 = 0 and a2x + b2y + c2 = 0, infinite solutions are possible when (a1/a2) = (b1/b2) = (c1/c2) In the given pair of equations, a1 = 5, a2 = 10, b1 = тИТ2, b2 = тИТ4, c1 = тИТ12 and c2 = тИТ24 Since, (5/10) = (тИТ2/тИТ4) = (тИТ12/тИТ24), therefore, infinite solutions are possible.

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