Question
For given pair of equations, how many solutions are
possible? 5x − 2y = 12 and 10x − 4y = 24Solution
For a pair of linear equations a1x + b1y + c1 = 0 and a2x + b2y + c2 = 0, infinite solutions are possible when (a1/a2) = (b1/b2) = (c1/c2) In the given pair of equations, a1 = 5, a2 = 10, b1 = −2, b2 = −4, c1 = −12 and c2 = −24 Since, (5/10) = (−2/−4) = (−12/−24), therefore, infinite solutions are possible.
More Linear Equation Questions
(√ 121 x 41) + (3√343 x √289 ) = ? x 19
7, 8, 12, 21, 37, ?
Evaluate: 72 ÷ 6 × (5 + 1) − 8² + 10
What will come in the place of question mark (?) in the given expression?
(30 × 5 + 20) × 2 = ?
What will come in the place of question mark (?) in the given expression?
737 + 149 - ?²- 367 = 14 X 25(√ 1444 ÷ 5) × 3.25 = ?
522 + 160% of 80 - 130 = ? X 13
54% of 250 = 6 × 21 + √?
300% of (3341 – 471) = ? × (√4225/195)
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