Question
Two ships are opposite a lighthouse such that all three
of them are collie Zār. The angles of depression of the two ships from the top of the light house 30º and 60º. If the ships are 230 √ 3m apart, then find the height of the light house (in m).Solution
As we know AD/DB=3/1 Then- 4=230√3 DB=1=230√3 /4 Now – Tan 60° =CD/DB √3 =CD /DB CD=√3 ×DB =√3×230√3/4 230×3/4=690/4 =172.5m
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