Question
The product of two numbers is 3600 and their HCF is 6.
Total number of such pairs of numbers is?  ÂSolution
As HCF is 6 so let numbers be 6x & 6y. It means x & y must be co-prime. Now 6x × 6y = 3600, So xy = 100. Now pairs of (x, y) can be (1,100) , (2,50) , (4, 25) , (5, 20) & (10, 10). Here only (1,100) & (4, 25) are co-prime so number of pairs are 2.Â
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