Question
Train X running at a speed of 32 km/hr crosses train Y
in 20 seconds. Find the speed of train Y (in km/hr), if the sum of the length of train X and Y is 650 meters and both trains running in the opposite direction.Solution
Let speed of train Y be 'a' km/hr. According to question, => 20(32 + a) × (5/18) = 650 => 640 + 20a = 2340 => 20a = 1700 => a = 85 km/hr
24.035 × √? = 4607.89 ÷ 11.8259Â
What approximate value will replace the question mark (?) in the following?
18.99...
‘A’ and ‘B’ can build a wall in 8 days and 12 days, respectively. If ‘A’ started building the wall alone but after 4 days he was replaced by...
14.99% of 7820 + 5535.25 ÷ 123.001 - ? = 84
[(2/3 of 899.79) + 25% of 500.21] × (√195.77 + 30.03% of 399.79) = ?
`root(3)(725.87)` `-:` `sqrt(81.033)` Â + 49.88% of 809.77 = ? - (14.78Â `xx` Â 52.2)
(?)2 + 3.113 = 22.92 – 61.03Â
(48.89 ÷ 7.08) × (35.96 ÷ 4.11) + (9.02 × 1.99) = ?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
30.02% of 420.11 + 44.96% of 499.96 - 203.12 = ?
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