Question
The smallest number which when divided by 28 and 32
leaves remainder 10 and 14 respectively is:Solution
The number = LCM (28, 32) â k, (where k = 28 â 10 = 32 â 14 = 18) LCM of 28 and 32 = 224 Subtract the common difference from 224, Required number will be = 224 - 18 = 206
What is the position of “20” from the right end in the last step?
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