Question
The smallest number which when divided by 28 and 32
leaves remainder 10 and 14 respectively is:Solution
The number = LCM (28, 32) – k, (where k = 28 – 10 = 32 – 14 = 18) LCM of 28 and 32 = 224 Subtract the common difference from 224, Required number will be = 224 - 18 = 206
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