Question
The LCM of two numbers is 40 times its HCF. If the
product of the numbers is 1440, find their HCF.Solution
LCM = 40 x HCF formula used LCM x HCF = Product of no.'s let HCF be a LCM = 40a Now, 40a x a = 1440 40a2 = 1440 a2 = 36 a = 6
More HCF and LCM Questions
If (9000) 5 = 59.049
What is least number which when successively divided by 6, 4 and 4 leaves a remainder 5, 3 and 3 respectively?
If a = radic;( 3/2) , then radic; (1+a) + radic; (1-a) = ?
...If 100.13 = 14 and ( 0.1)x = 140, then what is the value of x.
(3125) -3/5 = ?
3√4913+ 3√4.913 + 3√0.004913 = ?
(161051) -3/5 = ?
(5⁴) 5 × (25³)³ = ?
What will come in place of a?
169 1.7 x 13 2.5 x 169 1.5 = 13 a
(0.09) -1.5 = ?
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