Question
Find the HCF and LCM of 36, 45 and 60.
Solution
Prime factors: 36 = 2² × 3² 45 = 3² × 5 60 = 2² × 3 × 5 HCF = product of common primes with smallest powers = 3¹ = 3 LCM = product of all primes with highest powers = 2² × 3² × 5 = 4 × 9 × 5 = 180 Answer: HCF = 3, LCM = 180
More HCF and LCM Questions
- LCM of two numbers is 64 times of their HCF. Sum of the HCF and LCM is 975. If the first number is 960. Find the other number?
- Let N be the greatest number that will divide 82, 105, 128 leaving the same remainder in each case. Then sum of the digits in N is:
- The LCM of two numbers is 3600 while their HCF is 60. If one of the numbers is 600, then the other number is:
- Find the difference between sum of digits of LCM and HCF of 24, 36 and 90.
- The HCF and LCM of 2 numbers are 2 and 60 respectively. If one of the numbers is 14 more than the other, find the smaller number.
- The HCF of two numbers is 18 and their LCM is 540. If one of the numbers is 90, find the other number.
- Find the difference between sum of digits of LCM and HCF of 28, 42 and 70.
- Three numbers are in the ratio 5:6:9 respectively. If the HCF of the numbers is 2, then find the LCM of the numbers.
- The least number which when divided by 8, 10, 14, 16, and 20 leaves the same remainder 3 in each case, is:
- The sum of two numbers is 156 and their HCF is 26. Find how many such pairs can be formed.
Relevant for Exams:
