Question
Find the least number which when divided by 12, 15, and 20 leaves remainder 5 each time.
Solution
ATQ, Required number = LCM(12,15,20) + 5 12=2²×3, 15=3×5, 20=2²×5 => LCM = 2²×3×5 = 60 Least number = 60 + 5 = 65
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