Question
Let N be the greatest number that will divide 85, 116,
147 leaving the same remainder in each case. Then sum of the digits in N is:Solution
To find the greatest number that leaves common remainder in each case, The HCF of (116-85), (147-85), (147-116)Β = 31 In this case the number will be 31. And sum of digits will be = 4
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