Question
The LCM of two natural numbers is 12 times their HCF. If the product of given two numbers is 10,800, then find the LCM of the numbers.
Solution
Let the HCF of the number be 'H'. So, LCM = 12H Product of two numbers = Product of their HCF and LCM So, 12H X H = 10,800 Or, H2 = 900 Or, 'H' = 30 or, H = - 30 Since, HCF cannot be negative. So, 'H' = 30 Therefore, LCM = 12 X 30 = 360
More HCF and LCM Questions
- The LCM and the HCF of the numbers 27 and 81 are in the ratio:
- The LCM of two numbers is 432 and their HCF is 55. If one of the numbers is 132, the other number is:
- Find the smallest number which when divided by 3, 4, 5 and 6 gives remainder ‘2’ in each case?
- Sum of the two numbers is 49 and their HCF and LCM are 7 and 70, respectively. Find the sum of reciprocal of the given two numbers.
- If the ratio of two numbers is 8 : 9 and their HCF is 6 then their LCM will be :
- The LCM of two numbers is 5400 while their HCF is 90. If one of the numbers is 900, then the other number is:
- Â Find the HCF of 756, 1134 and 1386.
- What is the difference between the LCM and HCF of 36, 40?
- Find the least common multiple of (48/64), (36/54), and (24/72).
- What is the HCF of  (x4  - x2  - 6)   and  (x4  - 4x2  + 3) ? (a) x2  - 3                       (b)   x + 2  (c)  x + 3             ...