Question
The LCM of two natural numbers is 25 times their HCF.
If the product of given two numbers is 3600, then find the LCM of the numbers.ÂSolution
Let the HCF of the number be 'H'. So, LCM = 25H Product of two numbers = Product of their HCF and LCM So, 25H × H = 3600 Or, H² = 144 Or, H = 12 or H = –12 Since, HCF cannot be negative. So, H = 12 Therefore, LCM = 25 × 12 = 300Â
3, 7, 16, 35, ?, 153
51     53     109     332     ?     6686
...A number series is given below, which follows a specific pattern. If 'A' represents the 'x'th term and 'B' represents ...
31Â Â Â 32Â Â Â Â 41Â Â Â Â 66Â Â Â 115Â Â Â Â ?
48Â Â Â 83Â Â Â 118Â Â Â 153Â Â Â 188Â Â Â ?
22Â Â Â Â Â Â Â Â Â Â 62Â Â Â Â Â Â Â Â Â Â 178Â Â Â Â Â Â Â Â 522Â Â Â Â Â Â Â Â 1550Â Â Â Â Â Â ?
...16, 8, 8, ?, 24, 60
3 12 48 192 768 ?
412, 537, 573, 916, 980, ?
12 Â Â Â 11 Â Â Â Â 21 Â Â Â Â 62 Â Â Â Â ? Â Â Â Â Â 1234
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