Question
Ratio of two numbers 4:11 and their LCM is 1980. Find
the sum of the given two numbers.Solution
Let the two numbers be '4h' and '11h', where 'h' is the HCF of the two given numbers. Product of two numbers = (Product of LCM and HCF) of the given two numbers 4h × 11h = h × 1980 Or, 44h = 1980 So, 'h' = (1980 / 44) = 45 Therefore, the required sum = 4h + 11h = 15h = 15 × 45 = 675 Hence, option c
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