Question
What will be the greatest common divisor (GC
- D of (x² - 6x + 8) and (x² - 9x + 20).
Solution
(x² - 6x + 8) = x² - 4x - 2x + 8 = x(x - 4) - 2(x - 4) = (x - 4)(x - 2) x² - 9x + 20 = x² - 4x - 5x + 20 = x(x - 4) - 5(x - 4) = (x - 4)(x - 5) So, required GCD = (x - 4) Hence, option b.
More HCF and LCM Questions
- The HCF of 5453 and 6409 is 221, their LCM is:
- What is the least number which when divided by 3, 15 & 18 leave a remainder 6 in each case & it is also divisible by 12?
- Find the difference between sum of digits of LCM and HCF of 25, 50 and 75.
- The total and the difference of L.C.M and H.C.F of two numbers are 432 and 96. If one of the numbers is 24, what is the other number?
- What will be the greatest common divisor (GCD) of (x² - 6x + 8) and (x² - 9x + 20).
- The Highest Common Factor (HCF) and Least Common Multiple (LCM) of two numbers, X and Y, are given as 8 and 80, respectively. Additionally, the difference ...
- What is the unit digit of the number 'A' obtained by subtracting the largest two-digit prime number from the least common multiple (LCM) of all single-digi...
- Find the total number of Prime factor in the given expression? 315 × 56 × 68
- If the product of two numbers is 225 and their HCF is 15, then find the LCM of the given two numbers.
- What is the least number that should be multiplied to 735 so that it becomes divisible by 42?
Relevant for Exams:
