Question
What will be the greatest common divisor (GCD) of (x²
- 6x + 8) and (x² - 9x + 20).Solution
(x² - 6x + 8) = x² - 4x - 2x + 8 = x(x - 4) - 2(x - 4) = (x - 4)(x - 2) x² - 9x + 20 = x² - 4x - 5x + 20 = x(x - 4) - 5(x - 4) = (x - 4)(x - 5) So, required GCD = (x - 4) Hence, option b.
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