Question
Ratio of two numbers 5:9 and their LCM is 1260. Find the sum of the given two numbers.
Solution
Let the two numbers be '5h' and '9h', where 'h' is the HCF of the two given numbers. Product of two numbers = (Product of LCM and HCF) of the given two numbers 5h × 9h = h × 1260 Or, 45h = 1260 So, 'h' = (1260 / 45) = 28 Therefore, the required sum = 5h + 9h = 14h = 14 × 28 = 392 Hence, option b
More HCF and LCM Questions
- Find the smallest multiple of 10 that, when divided by 4, 6, and 9, leaves a remainder of 4 in each case.
- Find the HCF and LCM of 18 and 30.
- Find the largest number of the five digit which is exactly divisible by 48, 72 and 108.
- The sum of two numbers is 99 and their HCF is 9. Total number of such pairs of numbers is?
- The least number which when divided by 4, 6, 10 and 12 leave zero remainder in each case and when divided by 13 leaves a remainder of 8 is:
- The product of the two prime numbers is 187. What will the L.C.M of these two numbers?
- Find the difference between sum of digits of LCM and HCF of 25, 50 and 75.
- Find the HCF of 932 and 748.
- The LCM of two numbers is 168, and the numbers are in the ratio 4:7. Find the sum of the numbers.
- The HCF of two numbers is 12. If their product is 1728, then how many such pairs exist?
Relevant for Exams:
