The LCM of two numbers is 15 times their HCF.

Solution

Let HCF be x [if gte msEquation 12]>x [if !msEquation]-->[endif]-->, then LCM = 15x [if gte msEquation 12]>x [if !msEquation]-->[endif]--> It is given LCM + HCF = 352 [if gte msEquation 12]>x [if !msEquation]-->[endif]-->=> x + 15x [if gte msEquation 12]>x [if !msEquation]-->[endif]--> = 352 ⇒ 16x [if gte msEquation 12]>x [if !msEquation]-->[endif]--> = 352 [if gte msEquation 12]>∴ [if !msEquation]-->[endif]--> => x = 22 HCF = 22 and LCM = 15x = 15 × 22 = 330 Product of two numbers = Product of their HCF and LCM ⇒ 110 × other number = 22 × 330 => Other number = (22 × 330)/110 = 66