Question
The least number which when divided by 7, 12, 15 and 20 leave zero remainder in each case and when divided by 26 leaves a remainder of 4 is:
Solution
LCM of 7, 12, 15 and 20Â = 420 Required number = 420, because it is exactly divisible by 7, 12, 15 and 20Â and it leaves remainder 4 when divided by 26.
More HCF and LCM Questions
- A boy can swim in still water at a speed of 8 km/hr. If the speed of the current would have been 3 km/hr, then the boy could swim 55 km
- LCM of 21 5 , 21 10 and 21 15 is? (1). 21 5 (2). 21 15 (3).2130 (4 ). 21 10
- The least common multiple (LCM) of two numbers is 22 times their highest common factor (HCF). One of the numbers is 132, and the sum of the HCF and LCM is ...
- The product of two numbers is 5600 and their L.C.M is 280. What is the H.C.F of the two numbers?
- If total number of factors of 2,520 is 'y', then find the value of (y - 4)(y + 6).
- The square of sum of two numbers is 36,864 and the sum of squares of the same two numbers is 21,024. If their H.C.F. is 12, then find their L.C.M.Â
- The H.C.F. of two numbers is 16 and the other two factors of their L.C.M. are 4 and 13. The larger of the two numbers is:
- Find the difference between sum of digits of LCM and HCF of 16, 40 and 64.
- LCM of two numbers is 56 times their HCF, with the sum of their HCF and LCM being 1710. If one of the two numbers is 240, then what is the other number?
- The LCM of two natural numbers is 8 times their HCF. If the product of given two numbers is 1152, then find the LCM of the numbers.Â
Relevant for Exams:
