Question
The least number which when divided by 7, 12, 15 and 20 leave zero remainder in each case and when divided by 26 leaves a remainder of 4 is:
Solution
LCM of 7, 12, 15 and 20Â = 420 Required number = 420, because it is exactly divisible by 7, 12, 15 and 20Â and it leaves remainder 4 when divided by 26.
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