What is the HCF ofÂ Â (x4 Â - x2 Â - 6)Â Â Â andÂ Â (x4 Â - 4x2 Â + 3) ?

(a)Â x2 Â - 3Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â (b)Â Â Â x + 2

Â (c) Â x + 3Â Â Â Â Â Â Â Â Â Â Â Â Â (d)Â Â x2 Â + 3

x4 Â - x2 Â - 6 = (x2 Â - 3) (x2 + 2) And x4 Â - 4x2 Â +3 = (x2 Â - 3) (x2 Â -1) Â HCF = (x2 - 3)

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