Question
What is the HCF of (x4 - x2 - 6) and
(x4 - 4x2 + 3) ? (a) x2 - 3 (b) x + 2 (c) x + 3 (d) x2 + 3Solution
x4 - x2 - 6 = (x2 - 3) (x2 + 2) And x4 - 4x2 +3 = (x2 - 3) (x2 -1) HCF = (x2 - 3)
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