Question
The smallest number which when divided by 29 and 33
leaves remainder 11 and 15 respectively is:Solution
The number = LCM (29, 33) – k, (where k = 29 – 11 = 33 – 15 = 18) LCM of 29 and 33 = 957 Subtract the common difference from 957, Required number will be = 957 - 18 = 939
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