Question
Let N be the greatest number that will divide 90, 112, 134 leaving the same remainder in each case. Then sum of the digits in N is:
Solution
To find the greatest number that leaves common remainder in each case, The HCF of (112-90), (134-90), (134-112) = 22 In this case the number will be 22. And sum of digits will be = 4
More HCF and LCM Questions
- Calculate the number of factors of 480.
- The HCF of two numbers is 20. If their product is 16000, then how many such pairs exist?
- What is the difference between the LCM and HCF of 21, 49?
- Find the largest number of the five digit which is exactly divisible by 48, 72 and 108.
- Find the smallest 4-digit number that is exactly divisible by 14, 20 and 27.
- The HCF of two numbers is 12 and their LCM is 180. If one of the numbers is 36, find the other number.
- The greatest number, which when subtracted from 6254, gives a number exactly divisible by each of 20, 25, 30 and 35, is:
- The H.C.F of two numbers is 2 and their L.C.M is 117. If one of the numbers is 13, find the other?
- The square of sum of two numbers is 36,864 and the sum of squares of the same two numbers is 21,024. If their H.C.F. is 12, then find their L.C.M.
- If the product of two numbers is 3026 and their LCM is 89 then their HCF is:
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