Question
Let N be the greatest number that will divide 90, 112,
134 leaving the same remainder in each case. Then sum of the digits in N is:Solution
To find the greatest number that leaves common remainder in each case, The HCF of (112-90), (134-90), (134-112) = 22 In this case the number will be 22. And sum of digits will be = 4
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3, 8, 15, 24, 35, 50, 63Find the wrong number in the given number series.
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40, 56, 85, 129, 190, 268
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2, 5, 9, 14, 20, 28 95, 139, 191, 251, 319, 380
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27, 38, 52, 70, 94, 122 Find the wrong number, in the given number series,
1680, 840, 2520, 630, 3150, 475
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1, 2, 6, 24, 120, 600 15, 27, 51, 99, 193, 387
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