Start learning 50% faster. Sign in now
To find the greatest number that leaves common remainder in each case, The HCF of (112-90), (134-90), (134-112) = 22 In this case the number will be 22. And sum of digits will be = 4
1 5 36 343 ? 59049
...1 2 11 36 85 ?
...112 ? 336 840 2520 8820
...1 2 9 ? 65 126
...2, 12, 36, 80, ?, 252
If 204 196 223 x 284
Then, what is the average of the numbers of the above series?
...10 19 58 ...
105 107 111 114 ? 127
5 13 36 145 719 4321
12 10 13 18.5 25.50 �...