Question
Let N be the greatest number that will divide 92, 114,
136 leaving the same remainder in each case. Then sum of the digits in N is:Solution
To find the greatest number that leaves common remainder in each case, The HCF of (114-92), (136-92), (136-114) = 22 In this case the number will be 22. And sum of digits will be = 4
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Statements:
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Only a few Helium are Hydrogen.
Conclusion:
All Ni...
Answer the questions based on the information given below.
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