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LCM × HCF = a × b a = First number b = Second number => 55 × 432 = 132 × b => b = 180
Find the value of (cos 60 º + sin 60 º) /(tan 60 º + cot 45 º) .
If sin θ = 3/5 and cos θ = 4/5, find the value of (2tan² θ + 3cot² θ).
If cosec (2A + B) = (2/√3) and cosec (A + B) = √2, then determine the value of (4A - B).
If sin 28° = 15/17 , then tan 62° = ?
tan 1˚ × tan 2˚× …………………….tan 88˚ × tan 89˚ = ?
If 2cosA + secA = 2√2 , 0° < < 90°, then the value of 2(sec 4 A + cosec 4 A) is:
