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      Question

      The smallest number which when divided by 23 and 28

      leaves remainder 11 and 16 respectively is:
      A 553 Correct Answer Incorrect Answer
      B 206 Correct Answer Incorrect Answer
      C 632 Correct Answer Incorrect Answer
      D 362 Correct Answer Incorrect Answer

      Solution

      The number = LCM (23, 28) โ€“ k, (where k = 23 โ€“ 11 = 28 โ€“ 16 = 12) LCM of 23 and 28 = 644 Subtract the common difference from 644, Required number will be = 644 - 12 = 632

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