Question
The smallest number which when divided by 23 and 28
leaves remainder 11 and 16 respectively is:Solution
The number = LCM (23, 28) – k, (where k = 23 – 11 = 28 – 16 = 12) LCM of 23 and 28 = 644 Subtract the common difference from 644, Required number will be = 644 - 12 = 632
The ratio of two numbers is 5: 8 and their LCM is 320. What is the difference between these two numbers?
The HCF of each pair of 5 numbers is 3 and their LCM is 159. Find the multiplication of all the number.
If the product of two numbers is 108 and their HCF is 6, then find the LCM of the given two numbers.
Ratio of two numbers 6:13 and their LCM is 1950. Find the sum of the given two numbers.
What is the LCM of 2/3, 4/6, 8/27?
The HCF of two numbers is 72, and their LCM is 2160. What is the sum of the numbers?
The product of two numbers is 3600 and their GCD is 30. What is the LCM?
The HCF and LCM of two numbers, A and B, are 14 and 196, respectively. The difference between these two numbers is 28. Find their sum.
If total number of factors of 1,260 is 'x', then find the value of (x - 4) (x + 6).
