Question
The smallest number which when divided by 23 and 28
leaves remainder 11 and 16 respectively is:Solution
The number = LCM (23, 28) – k, (where k = 23 – 11 = 28 – 16 = 12) LCM of 23 and 28 = 644 Subtract the common difference from 644, Required number will be = 644 - 12 = 632
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