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    Question

    The smallest number which when divided by 23 and 28

    leaves remainder 11 and 16 respectively is:
    A 553 Correct Answer Incorrect Answer
    B 206 Correct Answer Incorrect Answer
    C 632 Correct Answer Incorrect Answer
    D 362 Correct Answer Incorrect Answer

    Solution

    The number = LCM (23, 28) – k, (where k = 23 – 11 = 28 – 16 = 12) LCM of 23 and 28 = 644 Subtract the common difference from 644, Required number will be = 644 - 12 = 632

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