ЁЯУв Too many exams? DonтАЩt know which one suits you best? Book Your Free Expert ЁЯСЙ call Now!

    Question

    The smallest number which when divided by 23 and 28

    leaves remainder 11 and 16 respectively is:
    A 553 Correct Answer Incorrect Answer
    B 206 Correct Answer Incorrect Answer
    C 632 Correct Answer Incorrect Answer
    D 362 Correct Answer Incorrect Answer

    Solution

    The number = LCM (23, 28) тАУ k, (where k = 23 тАУ 11 = 28 тАУ 16 = 12) LCM of 23 and 28 = 644 Subtract the common difference from 644, Required number will be = 644 - 12 = 632

    Practice Next
    More HCF and LCM Questions
    ask-question