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      Question

      Find the greatest number which when divide 49,145 & 241

      leave a same remainder 1 in each case?
      A 6 Correct Answer Incorrect Answer
      B 12 Correct Answer Incorrect Answer
      C 18 Correct Answer Incorrect Answer
      D 48 Correct Answer Incorrect Answer

      Solution

      The greatest number which when divide 49,145 & 241 leave a same remainder 1 in each case = HCF (49 - 1, 145 -1 , 241 - 1 ) = HCF (48, 144, 240 ) = 48.

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