Question
∆ ABC is similar to ∆ DEF. If area of ∆ABC is 9
sq.cm and area of ∆DEF is 16 sq.cm and BC = 2.1 cm. Then the length of EF will beSolution
If triangle are similar then (area of △ ABC) /( area of △ DE F) = BC2 / EF2 9/16 = BC2 / EF2 2.1 / EF = 3/4 EF = 2.8 cm
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