Question
In ∆ABC , G is the centroid , AB = 12 cm, BC= 16 cm and AC = 20 cm , find GD, where D is the mid-point of BC?
If AD is the median, then we know, AB² + AC² = 2{AD² + (BC/2)²} or 122 + 202 = 2{AD 2 + (16/2) 2 } or 144 + 400 = 2{AD 2 + 64} or 544/2 = AD 2 + 64 or 272 = AD 2 + 64 or AD 2 = 272 – 64 = 208 or AD = √208 = 4√13 Now G divides median in 2:1 so GD = 1/3 of AD = 1/3 of 4√13 = 4√13/3cmMore Geometry Questions
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