Question
A triangular field has sides 13 m, 14 m, and 15 m. A
well with a diameter of 7 m is dug outside the field. If the entire soil dug from the well is used to level the field, find the depth of the well.Solution
Area of triangle using Heron’s formula: s = (13 + 14 + 15) / 2 = 21 Area = √[21(21 - 13)(21 - 14)(21 - 15)] = √[21 × 8 × 7 × 6] = √7056 = 84 m² Volume of soil dug = Area of field × depth Volume of well = πr²h = (22/7) × (7/2)² × h = 77h 84 = 77h h = 84/77 = 1.09 m Correct option: a
81% of 1550 + 27² = ? + 1386 ÷ 22
510.11 ÷ 16.98 × 5.14 – 119.9 = √?Â
(0.89 3 + 1.64 3 +2.76 3 ) ÷ 5.89 = ?
√3601 × √(224) ÷ √102 = ?
? = 540.24 + 1022.97 – 11.992 Â
What approximate value will replace the question mark (?) in the following?
18.99...
?% of 1499.89 + 54.14 × 8 = 25.05% of 5568.08
(289.89 + 59.98) X 2.25 = ? X 49.66
? × [(16.87) 2 – (6.98) 2 ] = 5.04× 191.11
? = 49.83% of 39.72% of (45.011.99 – 4.98 2.04)
