Question
ABC is an isosceles triangle inscribed in a circle. If
AB = AC = 12β5 and BC = 24 cm then radius of circle isSolution
we know if we draw a κ± which AD is bisect BC in two equal part BD = DC = 12 Now apply PGT in βADC AD = 24 If 0 in centre of circle. then OD = (24 β r) Now apply PGT in βOBD we get r2 = (12)Β² + (24 β r)2 r2 β (24 β r )2 = 12Β² (r + 24 β r )(r β 24 + r) = 144 2r = 24 + 6 = 2r = 30 = r = 15
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