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      Question

      ABC is an isosceles triangle inscribed in a circle. If

      AB = AC = 12√5 and BC = 24 cm then radius of circle is
      A 10 cm Correct Answer Incorrect Answer
      B 15 cm Correct Answer Incorrect Answer
      C 12 cm Correct Answer Incorrect Answer
      D 14 cm Correct Answer Incorrect Answer

      Solution

      we know if we draw a Ʇ which AD is bisect BC in two equal part BD = DC = 12 Now apply PGT in βˆ†ADC AD = 24 If 0 in centre of circle. then OD = (24 – r) Now apply PGT in βˆ†OBD we get r2 = (12)Β² + (24 – r)2 r2 – (24 – r )2 = 12Β² (r + 24 – r )(r – 24 + r) = 144 2r = 24 + 6 = 2r = 30 = r = 15

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