Numerator of a fraction is 4 less than the denominator. If 6 and 7 are added to numerator and denominator of a fraction respectively, then fraction becomes 3/14 more than the initial fraction. Find the sum of numerator and denominator of the initial fraction.
Let the numerator of a fraction = x Denominator = x+4 As per the question, (x+6)/(x+4+7) - (x/(x+4)) (x+6)/(x+11) = (3/14) + x/(x+4) 3x2 +59x-204=0 X= 3, -68/3 X cant be negative Desired sum = 3+3+4 =10
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