Question
(I) 3x2 + 7x = 6 (II) 6(2y2 + 1) =
17 y In the following questions two equations numbered I and II are given. You have to solve both the equations. Give answer if;Solution
I. 3x2 + 7x = 6 or 3x2 + 9x - 2x - 6 = 0 (x+3) (3x-2) = 0 or x = -3, 2/3 II. 6 ( 2y2 +1) = 17y or 12y2 + 6 - 17y = 0 or 12y2 + 9y - 8y +6 = 0 or (4y - 3) ( 3y-2) = 0 y = 3/4 , 2/3 Hence y>=x
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