Which of the following numbers is completely divisible by 11?

ATQ, A number is divisible by 11 if the difference between the sum of its digits at odd positions and the sum of its digits at even positions is either 0 or a multiple of 11. (A) 4,72,915: Sum of odd position digits = 4 + 2 + 1 = 7. Sum of even position digits = 7 + 9 + 5 = 21. Difference = 21 - 7 = 14 (not divisible by 11). (B) 5,83,726: Sum of odd position digits = 5 + 3 + 2 = 10. Sum of even position digits = 8 + 7 + 6 = 21. Difference = 21 - 10 = 11, which is divisible by 11. (C) 6,19,428: Sum of odd position digits = 6 + 9 + 2 = 17. Sum of even position digits = 1 + 4 + 8 = 13. Difference = 17 - 13 = 4 (not divisible by 11). (D) 7,35,841: Sum of odd position digits = 7 + 5 + 4 = 16. Sum of even position digits = 3 + 8 + 1 = 12. Difference = 16 - 12 = 4 (not divisible by 11). Hence, the correct answer is B.