Question
A circular wire enclosing the area of 9,856 cm² is
bent to form a square. How much area will be enclosed by that wire?Solution
A = π × r2 ⇒ 9,856 = 22/7 × r2 r2 = 9,856 × 7/22 = 3136 r = √ 3136 = 56 cm Circumference = 2 π r = 2 × 22/7 × 56 = 352 cm Hence, perimeter of required square = 4a = 352 cm a = 88 cm Hence, required area = a² = 88 × 88 = 7,744 cm²
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