Question
What will be the Profit of Anuj is approximately what
percent of total profit? 'Anuj', 'Binod' and 'Chintu' invested in ratio 3: 5:7. After 4 months 'Binod' added Rs.1000 more in his investment and 'Anuj' withdrew Rs. 800 from his investment. After six months more 'Chintu' added to his investment an amount equal to (1/2) of the investment done by 'Anuj' in first four months and 'Binod' added 4/7 more than the investment done by 'Chintu' in first 10 months and withdrew Rs. 1000 at the same time, whereas 'Anuj' added to his investment an amount that is equal to investment done by 'Binod' in first four months. Ratio of profit of 'chintu' to total profit at the end of year is given as 145:358.Solution
ATQ, we can say that Let the investment of Anuj, Binod, and chintu is 3a, 5a and 7a. Investment of Anuj = 3a × 4 + (3a – 800) × 6 + (3a – 800 + 5x) × 2 = 46a – 6400 Rs. Investment of Binod = 5a × 4 + (5a + 1000) × 6 + (5a + 11a) × 2 = 82a + 6000 Rs. Investment of Chintu = 7a × 10 + (7a + 1.5a) × 2 = 87a Rs. 87a/(46a – 6400 + 82a + 6000 + 87a) = 145/358 3a × 358 = 5 × (215a – 400) 1074a = 1075a – 2000 a = 2000 Profit Ratio, Anuj : Binod : Chintu = (46 × 2000 – 6400) : (82 × 2000 + 6000) : (87 × 2000) Anuj : Binod : Chintu = (920 – 64) : (1640 + 60) : 1740 = 856 : 1700 : 1740 = 214 : 425 : 435 Hence required % will be (214/1074) × 100 = ATQ, we can say that Let the investment of Anuj, Binod, and chintu is 3a, 5a and 7a. Investment of Anuj = 3a × 4 + (3a – 800) × 6 + (3a – 800 + 5x) × 2 = 46a – 6400 Rs. Investment of Binod = 5a × 4 + (5a + 1000) × 6 + (5a + 11a) × 2 = 82a + 6000 Rs. Investment of Chintu = 7a × 10 + (7a + 1.5a) × 2 = 87a Rs. 87a/(46a – 6400 + 82a + 6000 + 87a) = 145/358 3a × 358 = 5 × (215a – 400) 1074a = 1075a – 2000 a = 2000 Profit Ratio, Anuj : Binod : Chintu = (46 × 2000 – 6400) : (82 × 2000 + 6000) : (87 × 2000) Anuj : Binod : Chintu = (920 – 64) : (1640 + 60) : 1740 = 856 : 1700 : 1740 = 214 : 425 : 435 Hence required % will be (214/1074) × 100 = 19.92%
If tan θ + cot θ = 2 where 0 < θ < 90 ; find the value of tan30 θ + cot 29 θ.
The Value of (sin38Ëš)/(cos52Ëš) + (cos12Ëš)/(sin78Ëš) - 4cos²60Ëš is
If x = (sin 30 ° + cos 30 ° )/sec 60 ° , then find the value of 4x.
Find the simplified value of:
(tan 40 º  + tan 20 º )/(1 - tan 40 º tan 20 º)
If sinAo = (√3/2), then find the value of (sin245o + cos230o) × A ÷ 5 given that 0 < A < 90...
If 2ycosθ = x sinθ and 2xsecθ – ycosecθ = 3, then x 2 + 4y 2 = ?
If sin x + cos x = √2 sin x, then the value of sin x - cos x is:
If 2 sec 3x = 4, then the value of x:
The value of (sin 60 º cos 30 º - cos 60 º sin 30 º)  is equal to:
- Simplify the following trigonometric expression:
11 sin 42° sec 48° − 7 tan 37° tan 53°
Relevant for Exams:
