Question
Calculate the area of a sector of a circle having a radius
of 21 cm, if the angle at the center made by the sector is 60°.Solution
ATQ,
Area of sector = (A/360) × π × radius² (Here 'A' is the angle subtended by sector at centre)
So, required area = (60/360) × (22/7) × 21²
= (1/6) × (22/7) × 441
= 231 cm²
√4761 ÷ 23 + √12769 = ? × 58
(1748 ÷ 8) + 76.8 × 35 =(? × 4) + (42 × 35.5)
(√1296 – 12) × 5 = ? + 40
What will come in the place of question mark (?) in the given expression?
435 ÷ 29 X 792 ÷ 44 = √(? + 14) + 35 + 221 ÷ 17
...? = 65% of 40% of (20 × 250) − 200
[4(1/2) + 4(1/3)] × 12 – 42 = ?2
∛857375 + ∛91125 = ? + √6889
35% of 240 – 6 2 = ? 2 – √256
30% of 600 –