Question
Two chords AB and CD of a circle intersect at E such
that AE = 3.4 cm, BE = 4.2 cm and CE = 2.6 cm. What is the approximate length of DE?Solution
The Intersecting Chord Theorem states that when two chords intersect each other inside a circle, the products of their segments are equal. ⇒ AE * BE = CE * DE ⇒ 3.4 * 4.2 = 2.6 * DE ⇒ DE = 5.49 ≈ 5.5
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