Question
The ratio of the speed of a boat in still water to its
speed in downstream is 6:8. If the difference between the time taken by the boat to travel 288 km each in upstream and in downstream is 3 hours, then find the speed of the boat in still water.Solution
ATQ, Let the speed of the boat in still water and its speed in downstream be '6y' km/h and '8y' km/h. So, speed of the stream = 8y - 6y = '2y' km/h And, speed of the boat in upstream = 6y - 2y = '4y' km/h According to the question, 
Hence, speed of boat in still water is 6y = 12×6 = 72
If p = 24 - q - r and pq + r(q + p) = 132, then find the value of (p² + q² + r²).
((99.9 - 20.9)² + (99.9 + 20.9)² )/(99.9 x 99.9 + 20.9 x 20.9) = ?
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Find the value of the given expression-
(4x+4 -5× 4x+2) / 15×4x – 22×4x
If 4x² + y² = 40 and x y = 6, then find the value
of 2x + y?
If p = 40 - q - r and pq + r(q + p) = 432, then find the value of (p² + q² + r²).
47.98 × 4.16 + √325 × 12.91 + ? = 79.93 × 5.91
If x + y = 4 and (1/x) + (1/y) = 24/7, then the value of (x3 + y3).
- If p = 20 - q - r and pq + r(p + q) = 154, then find the value of (p² + q² + r²).
If a = (√2 - 1)1/3, then the value of (a-1/a)3 +3(a-1/a) is:
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