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ATQ, Let the speed of the stream be 10x km/hr. So, speed of the boat in still water = 1.5×10x=15x km/hr ATQ, 
Speed of stream = 10x = 10.8 km/hr Now, Reduced speed of boat in still water = 15x × 0.8 = 12 km/hr Therefore, required distance = (12−10.8)×5 = 6 km
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