Question
A man can row at 5 kmph in still water. If the velocity
of current is 3 kmph and it takes him 5 hour to row to a place and come back, how far is the place?Solution
Let the distance be x km. Speed upstream = 5 – 3 = 2 kmph Speed downstream = 5 + 3 = 8 kmph => (x/8) + (x/2) = 5 => (x + 4x)/8 = 5 => 5x = 40 => x = 8 km
12.052 + 36.15 × 25.45 – 124.15 × 15.05 = ? × 8.08 – 64.32 × 15.98
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
(48.89 ÷ 7.08) × (35.96 ÷ 4.11) + (9.02 × 1.99) = ?
35.05% of 14.87 × (13.02 – ?) + 30.19 = 188.7
40.02% of 1220.05 = ?2 + 29.09 × 7.99
√2401 × (√2116 ÷ 23) × 21 ÷ 3 = ?
49.99% of 639.99 + 159.98% of 49.99 = ?2
480 ÷ 10 + 18 % of 160 + ? * 9 = 60 * √36
(24.98)2 = ?2Â + (14.99)2
1449.98 ÷ 50.48 × 10.12 = ? × 2.16