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    Question

    The average price of 10 stickers is Rs.12 while the

    average price of 8 of these stickers is Rs.11.75. Of the remaining two stickers, if the price of one sticker is 60% more than the price of the other, then what is the price of each of these two stickers?
    A Rs. 10, 16 Correct Answer Incorrect Answer
    B Rs. 31.2, 46.8 Correct Answer Incorrect Answer
    C Rs. 20, 30 Correct Answer Incorrect Answer
    D Rs. 25, 30 Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    Total cost of 10 stickers = 10*12 = Rs. 120 Total cost of 8 stickers = 8*11.75= Rs. 94 => The cost of remaining 2 stickers = 120- 94 = Rs. 26 Let the price of each sticker be x and y. => x + y = 26---------------- (1) And x = 160% of y = 1.6y => 2.6y = 26 y = 26/2.6= 10 and x = 26- 10= 16 So, the price of each of the two stickers is Rs. 10 and Rs. 16 respectively.

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