Question
The average price of 10 stickers is Rs.12 while the
average price of 8 of these stickers is Rs.11.75. Of the remaining two stickers, if the price of one sticker is 60% more than the price of the other, then what is the price of each of these two stickers?Solution
Total cost of 10 stickers = 10*12 = Rs. 120 Total cost of 8 stickers = 8*11.75= Rs. 94 => The cost of remaining 2 stickers = 120- 94 = Rs. 26 Let the price of each sticker be x and y. => x + y = 26---------------- (1) And x = 160% of y = 1.6y => 2.6y = 26 y = 26/2.6= 10 and x = 26- 10= 16 So, the price of each of the two stickers is Rs. 10 and Rs. 16 respectively.
564.932 + 849.029 – 425.08 = 612.095 + ?
999.99 + 99.99 + 99= ?
A sum of ₹60,000 is invested at a compound interest rate of 'x%' per annum, compounded annually, and grows to ₹75,264 in 2 ye...
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
³√? × 33.97 + 59.99 × 28.9 – 48.98 × 21.42 = 1085.344
1279.98 ÷ 40.48 × 10.12 = ? × 2.16
(124.901) × (11.93) + 219.95 = ? + 114.891 × 13.90
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
Relevant for Exams:
