Question
The average price of 10 stickers is Rs.12 while the
average price of 8 of these stickers is Rs.11.75. Of the remaining two stickers, if the price of one sticker is 60% more than the price of the other, then what is the price of each of these two stickers?Solution
Total cost of 10 stickers = 10*12 = Rs. 120 Total cost of 8 stickers = 8*11.75= Rs. 94 => The cost of remaining 2 stickers = 120- 94 = Rs. 26 Let the price of each sticker be x and y. => x + y = 26---------------- (1) And x = 160% of y = 1.6y => 2.6y = 26 y = 26/2.6= 10 and x = 26- 10= 16 So, the price of each of the two stickers is Rs. 10 and Rs. 16 respectively.
√10404 + √9604 - ∛1728 - ∛42875 = ?
1299.999 ÷ 325.018 × 24.996 = ?
24% of 400 × 16% of ? = 384
Determine the simplified value of the given mathematical expression.
What will come in the place of question mark (?) in the given expression?
(144 × 16 ÷ 12) × 6 = ?Â
82% of 400 + √(?) = 130% of 600 - 85% of 400
192.251 + 326.233 + 125.021 + 19.273 = ?
45% of 360 - 160 + ? = √324
(160 × 12 - 13 × 20)/(120 × 2 + 2 × 35 + 2 × 11) = ?
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