Question
The average price of 10 stickers is Rs.12 while the
average price of 8 of these stickers is Rs.11.75. Of the remaining two stickers, if the price of one sticker is 60% more than the price of the other, then what is the price of each of these two stickers?Solution
Total cost of 10 stickers = 10*12 = Rs. 120 Total cost of 8 stickers = 8*11.75= Rs. 94 => The cost of remaining 2 stickers = 120- 94 = Rs. 26 Let the price of each sticker be x and y. => x + y = 26---------------- (1) And x = 160% of y = 1.6y => 2.6y = 26 y = 26/2.6= 10 and x = 26- 10= 16 So, the price of each of the two stickers is Rs. 10 and Rs. 16 respectively.
18% of 200 - 16% of 150 = ?
(12% of 1250 + 85% of 400) x 10 = ?2
What is (0.08% of 0.008% of 8)1/9 ?
1540 ÷ 7 - 184 ÷ 8 = ?
{(81% of 800 + 28 × 4) – 27 × ?} = 11 × 20
? ÷ 62 × 12 = 264
- Evaluate: 156 ÷ 12 × 4 + 180 – 40% of 350
25% of 1000 + 10% of 150 – 22 × ? = 45
- Find the simplified value of the given expression.
672 ÷ 28 × 24 + 363 – 309 =?