Question
Average of nine consecutive numbers is 56. Find the sum
of smallest and largest number.Solution
Let the numbers be (a - 4), (a - 3), (a - 2), (a - 1), a, (a + 1), (a + 2), (a + 3) and (a + 4).
So, (a - 4 + a - 3 + a - 2 + a - 1 + a + a + 1 + a + 2 + a + 3 + a + 4) ÷ 9 = 56
Or, (9a/9) = 56
Or, 'a' = 56
Required sum = a - 4 + a + 4 = 2a = 2 × 56 = 112
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