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    Question

    What is the average of the squares of the first 11 natural

    numbers?
    A 42 Correct Answer Incorrect Answer
    B 44 Correct Answer Incorrect Answer
    C 46 Correct Answer Incorrect Answer
    D 48 Correct Answer Incorrect Answer

    Solution

    Sum of squares of first 'n' natural numbers = n Ă— (n + 1) Ă— (2n + 1) Ă· 6
    So, average = n Ă— (n + 1) Ă— (2n + 1) Ă· 6n = (n + 1) Ă— (2n + 1) Ă· 6
    = (11 + 1) Ă— (2 Ă— 11 + 1) Ă· 6
    = 12 Ă— 23 Ă· 6
    = 46

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