Question
In a school club, the ratio of juniors to seniors is
3:2. The average score of all seniors is (x β 2) and the average score of all members is (x + 4). What is the average score of juniors?Solution
Let number of juniors and seniors be '3a' and '2a', respectively.
Total score of the club = 5a Γ (x + 4) = 5ax + 20a
Total score of seniors = 2a Γ (x β 2) = 2ax β 4a
So, total score of juniors = (5ax + 20a) β (2ax β 4a) = 3ax + 24a
Therefore, average score of juniors = (3ax + 24a) / 3a = (x + 8)
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