Question
The average of 30 numbers is 55. The average of the
first 15 numbers is 50 and the average of the last 12 numbers is 55. What is the average of 68, 74 and the remaining 3 numbers?Solution
Sum of all 30 terms = 30 x 55= 1650 Sum of first 15 terms = 15× 50 = 750 Sum of last 12 terms = 12 x 55 = 660 After removing the first 15 and last 12 terms, there will be 3 terms remaining.  Sum of remaining 3 terms = 1650 (750 +660) = 240 According to the question, 68 and 74 are added to the sum of 3 terms. Thus, the number of total terms becomes 5. Average of 5 terms = (240 +68 + 74)/5 382/5= 76.4  76.4 is the average of 68, 74 and the remaining 3 numbers.
What will be the remainder when 742 is divided by 48?
Which of the following pairs of non-zero values of p and q make 6-digit number 674pq0 divisible by both 3 and 11?
When a number is divided by 23, the quotient obtained is 168, and the difference between the quotient and the remainder is 152. Determine the number.
Find the smallest number that, when divided by 6, 8, and 12, leaves a remainder of 5 in each case.
An eight-digit number, 9x54y32 is divisible by 72. Find the maximum possible value of x + y.
Find the remainder when 2722 is divided by 729.
Which of the following numbers is divisible by 11?
If 'x' is the lowest positive integer divisible by 14, 22 and 30, then find the second smallest positive integer which is divisible by all the three gi...
The difference between the two numbers is 1980. The quotient and remainder are respectively 20 and 4 when the larger number is divided by the smaller on...
If a nine-digit number 89563x87y is divisible by 72, then the value of √ (5x -4y) will be ∶
Relevant for Exams:
