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    Question

    Average of nine consecutive numbers is 65. Find the sum

    of smallest and largest number.
    A 126 Correct Answer Incorrect Answer
    B 128 Correct Answer Incorrect Answer
    C 130 Correct Answer Incorrect Answer
    D 132 Correct Answer Incorrect Answer

    Solution

    Let the numbers be (a - 4), (a - 3), (a - 2), (a - 1), a, (a + 1), (a + 2), (a + 3) and (a + 4).
    So, (a - 4 + a - 3 + a - 2 + a - 1 + a + a + 1 + a + 2 + a + 3 + a + 4) ├╖ 9 = 65
    Or, (9a/9) = 65
    Or, 'a' = 65
    Required sum = a - 4 + a + 4 = 2a = 2 ├Ч 65 = 130

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