Question
The average of the present age of 'S' and 'T' is 40 years.
If the ratio of the age of 'S' 5 years ago to the age of 'T' 5 years hence is 3:5, then find the age of 'T' 10 years hence from now.Solution
ATQ,
Let the age of 'S' 5 years ago be 3x years.
Let the age of 'T' 5 years hence be 5x years.
So, the present age of 'S' = (3x + 5) years
So, the present age of 'T' = (5x - 5) years
So, the sum of the present age of 'S' and 'T' = 40 × 2 = 80 years
So, 3x + 5 + 5x - 5 = 80
So, 8x = 80
So, x = 10
So, present age of 'T' = 5x - 5 = 50 - 5 = 45 years
So, the age of 'T' 10 years hence from now = 45 + 10 = 55 years
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