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      Question

      The average of the present age of 'S' and 'T' is 40 years.

      If the ratio of the age of 'S' 5 years ago to the age of 'T' 5 years hence is 3:5, then find the age of 'T' 10 years hence from now.
      A 35 yrs Correct Answer Incorrect Answer
      B 42 yrs Correct Answer Incorrect Answer
      C 49 yrs Correct Answer Incorrect Answer
      D 55 yrs Correct Answer Incorrect Answer
      E None of these Correct Answer Incorrect Answer

      Solution

      ATQ,

      Let the age of 'S' 5 years ago be 3x years.

      Let the age of 'T' 5 years hence be 5x years.

      So, the present age of 'S' = (3x + 5) years

      So, the present age of 'T' = (5x - 5) years

      So, the sum of the present age of 'S' and 'T' = 40 × 2 = 80 years

      So, 3x + 5 + 5x - 5 = 80

      So, 8x = 80

      So, x = 10

      So, present age of 'T' = 5x - 5 = 50 - 5 = 45 years

      So, the age of 'T' 10 years hence from now = 45 + 10 = 55 years

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