Question
Given that the average of 21, 38, 62, 53, 35, and 'x' is
48, what is the value of 'x²'?Solution
ATQ,
21 + 38 + 62 + 53 + 35 + x = 48 × 6
Or, x = 288 - (21 + 38 + 62 + 53 + 35)
So, x = 79
So, required value = 79² = 6241
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