Question
There are 5 consecutive odd and 3 consecutive even
numbers. The sum of five consecutive odd numbers is 145 and the lowest even number is 6 more than twice the average of 5 consecutive odd numbers. Find the ratio between the lowest odd number and the highest even number.Solution
Let the 5 consecutive odd numbers be: x, x+2, x+4, x+6, x+8 Sum = 145 => 5x + 20 = 145 => 5x = 125 => x = 25 Lowest odd number = 25 Average = 145/5 = 29 Lowest even number = 2*(29) + 6 = 64 3 consecutive even numbers: 64, 66, 68 Highest even number = 68 Required ratio = 25 : 68
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