Practice Approximation Questions and Answers
- (363.89% of 224.98 β 319.86% of 134.94) Γ· ? = β(134.88 Γ· 15.25)
- 447.79 Γ· β(β2400) + 30.94 Γ 6.07 β 5.08 Γ 21.96 = ?
- ?% of 549.83 β 18.05 Γ 31.96 = 44.94% of 479.84 β 13.98 Γ 33.13Β
- 31.98% of 224.99 = 24.98% of ? + 9.91% of 499.99Β
- ?2 + (39.99 Γ 10.99 + 7.01) - (39.99 Γ 2.992 + 21.99) = 21.99 Γ 23.01
- 24.99 Γ 32.05 + ? - 27.01 Γ 19.97 = 29.99 Γ 27.98
- 23.95% of 274.99 - 34.99% of 120.01 = 19.95% of ?
- 79.95 Γ 25.001 β 20.001 Γ 129.90 + 839.99 = ?
- 74.91% of 639.95 β 599.98% of 45 + 119.987 = ?
- 564.932 + 849.029 β 425.08 = 612.095 + ?
- (519.98 + ?) Γ· 13.01 = β440 + 20.0
- (84.92 + 235.17) Γ· (15.93 Γ 3.89) = ? Γ· 21.02
- (1295.98)(1/4) + {40.02% of 150.09} Γ {β48.98 β β15.98} = ?
- 40.024 of 54.89% of 19.9 = ? Γ β(2661.98/22.09)Β
- (44.11/4.01) + (11.99/3.03) + 23.9% of 49.978 = ?3.03
- ?3 - (77.98 Γ· 6.09 + 10.12)2 + (2.015 - 11.983)2 = 20.01 Γ (215.98(2/3) - β36.03)
- 35.05% of 14.87 Γ (13.02 β ?) + 30.19 = 188.7
- (18.22) 2.02 + (13.89) 2.12 β (44.88) 2.07 = ? β 1604.85Β
- ? Γ 32.91 β 847.95 Γ· β16.4 β 13.982 = β24.7 Γ 24.04
- (? + 6.063.03 ) Γ· 10.08 + 21.89 Γ 6.97 = 1979.97 Γ· 10.96
- 185.92 Γ· 5.98 - (4.002Β 2 + 114.03 of 5.03 Γ· 18.99 of 6.04 = 5.01 of 2.99 + ? Γ· 12.02
- 45.1298% of (14.032 - 75.98) + 27.87% of β40001 = 449.98% of 24.098 + ?Β
- 16.01(? Γ 8.09 Γ· 16.09) = 3.01 of 69.69 + 14.12 of 4.01 - 100.998 of 2.19
- ? = 44.78% of 839.91 β 48.12% of 774.89 + 55.77% of 1024.85
- (462.23 Γ 127.84 Γ· 153.88) Γ· β(31.98 Γ 7.92) = ? Γ· 15.15
- (71.78 Γ 59.88 Γ· 17.92 Γ· 120.22 Γ 161.72)% of 32 = ?
- 3374.89% of 31.80 β 1739.85% of 44.72 = (?2 )% of 1188.13Β
- 837.04 Γ 4.02 + 40.04% of 3049.98 β 3667.82 = ? 2 β 60.87
- Β 15.78% of (287 + 302) + 12Β³ = ?% of 170 + 8 Γ 14 + 3Β²Β
- 12.5% of 6400 + (17 Γ 25) = ?% of 2200+ 125Β
- Β ?Β² Γ 55% of (29 + 32 - 41) = 41.66% of 216 + 9
- β49 + 6.66% of 1725 + 22Β² = ?Β² - β361Β
- Β (3/5) of 3025 + (18Β² + 12Β²) = ? + 22.22% of 1125
- The speed of the boat in still water is 20% less than the speed of the boat in downstream. The time taken by the boat to cover 780 km distance in upstream ...
- 12.05% of 1399. 93 + 24.95 Γ 15.05 - 319.04 = ?Β
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