Question
If x² + y² + z² = xy + yz + zy (x≠0),
then the value of (5x+3y-4z)/2x isSolution
x² + y² + z² = xy + yz + zx (x≠0) If x² + y² + z² - xy - yz - zx = 0 Then x = y = z (5x+3y-4z)/2x = (5x+3x-4x)/2x = 4x/2x = 2
More Algebra Questions
- If [4a - (1/2a)] = 6, then find the value of [16a² + (1/4a²) - 8]
If
= 2 then find If (x –1.3)3+(x–1.4)3+(x–1.5)3 = 3(x–1.3)(x–1.4)(x–1.5), Then x = ?
If (x2 + y2) = 9 and (xy)2 = 3, then find the value of (x4 + y4).
If sin 28° = 15/17 , then tan 62° = ?
√(92×8 ×52+700) = ?
- If (p + q + r) = 10 and (pq + qr + rp) = 30, then find the value of (p² + q² + r²).
Suppose xy = -15 and (x² + y²) = 34, then determine the value of (x – y).
Relevant for Exams:
