Question
If x² + y² + z² = xy + yz + zy (x≠0),
then the value of (5x+3y-4z)/2x isSolution
x² + y² + z² = xy + yz + zx (x≠0) If x² + y² + z² - xy - yz - zx = 0 Then x = y = z (5x+3y-4z)/2x = (5x+3x-4x)/2x = 4x/2x = 2
625, 5, 125, 25, 25, ? , 5
21 23 26 ? 39 51
...Identify the logic of the below given series and given answer.
Series I :: 1840, 1719, (P), 1694, 1890, 1665, 1921
Series II :: 175, 4...
96Â Â Â 111Â Â Â 131Â Â Â ? Â Â Â Â Â 186Â Â Â Â 221
Choose the correct alternative
21: 3 ∷ 574: ?
A sequence {Tₙ} is defined by: Tₙ = a·n² + b·n + c for all positive integers n, where a, b, c are constants.
It is known that - Tâ‚‚ = 11,...
16    9    11   26    ?    912
The number of terms in the sequence 20, 25, 30, ….., 160 is:
70    191    47    216    ?    245
12 78 385 ? 4629 9260
...