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Formula used: l = a + (n – 1)d Here, l = last term a = first term n = number of terms d = difference between two term (t – t ) Accordint to question, => d = t2 – t1 = 25 – 20 = 5 Let the number of terms be n. ⇒ 160 = 20 + (n – 1)5 ⇒ 140 = (n – 1)5 ⇒ n = 29 ∴ Number of terms = 29
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